Lesson 67 — Consolidation and Check: Properties of Quadrilaterals

Strand: Space | Descriptor: AC9M8SP02 | Duration: 45 minutes

Learning Intentions

  • To consolidate the side, angle and diagonal properties of parallelograms, rectangles, rhombuses, squares, kites and trapeziums.
  • To consolidate proof-writing skill using congruent triangles and angle reasoning.

Success Criteria

I can:

  1. Recall and state the side, angle and diagonal properties of each named quadrilateral.
  2. Select the correct property to solve a numeric problem, justifying with reasoning.
  3. Write a short formal proof using congruent triangles or angle properties.
  4. Identify a quadrilateral from a list of given properties, working backwards.

Warmup

(6 minutes — “Always, sometimes, never”, pairs)

  1. A rectangle is a rhombus.
  2. A parallelogram’s diagonals are perpendicular.
  3. A kite has two axes of symmetry.
  4. A trapezium’s diagonals bisect each other.

Answers: 1. Sometimes — only when it is also a square. 2. Sometimes — only for rhombi (a special parallelogram). 3. Never (for a proper kite) — a kite has exactly one axis of symmetry, along the diagonal joining the vertices between the equal sides. 4. Never, in general — this property belongs only to parallelograms (and a trapezium is not a parallelogram unless both pairs of sides happen to be parallel, in which case it wouldn’t properly be called a trapezium).

Activities

Activity 1 — Mixed Fluency Review (13 min)

Rapid-fire, then pair check.

I do/We do: Recap the full property table on the board:

ShapeSidesAnglesDiagonals
ParallelogramOpposite sides equalOpposite angles equalBisect each other
RectangleOpposite sides equalAll angles Bisect each other, equal
RhombusAll sides equalOpposite angles equalBisect each other at , bisect vertex angles
SquareAll sides equalAll angles Bisect each other at , equal, bisect vertex angles
KiteTwo pairs of adjacent sides equalOne pair of opposite angles equalPerpendicular, one bisected by the other
TrapeziumNo general side propertyCo-interior angles on the parallel sides sum to No general property

You do: For each of six mixed numeric prompts (sides, angles, or diagonal lengths given as expressions), students solve and name the property used, e.g. “Rhombus side , other side , find ,” “Kite , find .”

Activity 2 — Applied and Backwards-reasoning Problems (20 min)

Pairs.

Problem 1. A parallelogram has and . Find and all four angles.

Problem 2. A rhombus has diagonals cm and cm. Find the side length. (Links to the right-triangle idea previewed in Lesson 65 — full method arrives in Lesson 69.)

Problem 3. A quadrilateral has all four sides equal and its diagonals are also equal. What specific shape must it be? Justify.

Problem 4. A quadrilateral has diagonals that bisect each other and are equal in length. Prove it must be a rectangle.

Socratic scaffolding for Problem 4:

PromptPurpose
Understand: what two facts are given?Diagonals bisect each other (so it’s a parallelogram, Lesson 66) and they are equal in length.
Devise a planUse the equal-diagonal fact with SSS on two triangles formed by a diagonal and the two half-diagonals.
Carry out the planIn and : (given), (parallelogram property), common — SSS, so , giving .
Combine with a known fact and are co-interior (), so they also sum to .
Carry out the final stepEqual and summing to forces each to be .
Looking backDoes this match Activity 1’s table? Yes — a parallelogram with equal, bisecting diagonals is exactly the rectangle row.

Answers: 1. (co-interior) ; , , , ; 2. Half-diagonals cm and cm form a right triangle with the side as hypotenuse: side cm; 3. A square — equal sides makes it (at least) a rhombus, and equal diagonals on a rhombus forces all angles to (as shown in Problem 4’s method), giving a rhombus that is also a rectangle, i.e. a square; 4. See scaffold above.

Checks for Understanding

(6 minutes — exit ticket, collected)

  1. Name the quadrilateral with all sides equal but angles not necessarily .
  2. A rectangle has diagonal cm. What is the other diagonal?
  3. A kite has (the angle between the equal sides at the “top”). What can you say about the diagonal through ?
  4. A parallelogram has and (co-interior). Find .
  5. Reasoning. Explain why “a quadrilateral with four equal sides” is not, by itself, enough information to call it a square.

Answers: 1. Rhombus; 2. cm — a rectangle’s diagonals are equal; 3. It bisects into two parts; 4. ; 5. Four equal sides only guarantees a rhombus; without knowing the angles are (or that the diagonals are equal), it could be a “squashed” rhombus rather than a square.

Common Misconceptions

MisconceptionHow to pre-empt it
Treating “rhombus” and “square” as interchangeable.Always test with a clearly non-right-angled rhombus sketch alongside a square.
Believing every trapezium property matches a parallelogram property.Repeatedly contrast: trapezium has no general side, opposite-angle, or diagonal-bisection guarantee.
Forgetting that a square inherits properties from both the rectangle and the rhombus families.Use a nested Venn diagram (square rhombus rectangle parallelogram) as a permanent visual reference.
Working backwards (property list shape name) by pattern-matching on vocabulary rather than checking every given property.Insist students verify each listed property against the candidate shape’s full definition, not just one matching feature.
Assuming a numeric answer without stating which property justified the equation.Deduct marks (formatively) for correct numeric answers with no named property.

Enrichment — Competition-Style Problems

E1 (AMC Junior style). A quadrilateral has perpendicular diagonals that bisect each other but are not equal in length. What is the most specific name for this shape?

Answer

A rhombus (that is not a square) — perpendicular bisecting diagonals of unequal length is exactly the rhombus case (see Lesson 66, E1).

E2 (Kangaroo style). The four angles of a quadrilateral are in arithmetic sequence (each term increases by the same amount). The smallest angle is and the largest is . Find the common difference.

Answer

Angles: with sum . .

E3 (Challenge — Varignon revisited). A quadrilateral’s midpoint-parallelogram (Lesson 66, E3) turns out to be a rectangle. What must be true about the original quadrilateral’s diagonals?

Answer

The original diagonals must be perpendicular. Since each side of the midpoint parallelogram is parallel to a diagonal of the original shape, a right angle in the midpoint parallelogram corresponds directly to the two original diagonals meeting at .

Homework

  1. Complete a blank property table (sides, angles, diagonals) for: parallelogram, rectangle, rhombus, square, kite, trapezium.
  2. A rhombus has diagonals cm and cm. Find its side length.
  3. A parallelogram has and . Find .
  4. A quadrilateral has two pairs of adjacent equal sides but its diagonals are not perpendicular. Explain why it cannot be a kite in the standard sense — what has likely gone wrong in the description?
  5. Reasoning. Explain, using the nested Venn diagram idea, why “every square is a rectangle” is true but “every rectangle is a square” is false.
  6. Challenge. A quadrilateral has and . Prove it is a parallelogram, and then state one additional single fact that, if also true, would prove it is a rectangle.

Answers: 1. As per Activity 1’s table; 2. Half-diagonals cm, cm; side cm; 3. ; 4. In a true kite, perpendicular diagonals are a proven consequence of the two pairs of adjacent equal sides (Lesson 66-style SSS argument) — if the diagonals are not perpendicular, the “equal adjacent sides” premise must be mis-measured or mis-stated, since a genuine kite always produces perpendicular diagonals; 5. A square satisfies every property required to be a rectangle (four right angles, opposite sides equal), so it sits inside the rectangle set; but a general rectangle need not have all sides equal, so it does not automatically sit inside the square set; 6. Draw diagonal : gives (alternate angles), with and common, so (SAS), giving and , which are alternate angles proving — both pairs of sides are parallel, so is a parallelogram. One additional fact that would prove it a rectangle: the diagonals and are equal in length (or, equivalently, one angle is ).