Lesson 24 — Problem Solving with Irregular and Composite Shapes
Strand: Measurement | Descriptor: AC9M8M01 | Duration: 45 minutes
Learning Intentions
- To solve multi-step practical problems involving the area and perimeter of irregular and composite shapes.
- To work backwards from a given area or perimeter to find an unknown dimension.
Success Criteria
I can:
- Solve multi-step problems combining area (materials) and perimeter (boundary) for the same composite shape.
- Work backwards from a known area or perimeter to find a missing dimension.
- Justify a rounding decision appropriate to the real context.
- Communicate a full solution clearly, with a diagram, working and a concluding sentence.
Warmup
(6 minutes — mixed retrieval, mini whiteboards)
- A rectangle has area
and one side cm. Find the other side. - An L-shape’s bounding rectangle is
m by m, and the L-shape’s own area is . Find the area of the notch removed. - A composite shape (single corner notch) has perimeter
m. One pair of bounding-rectangle sides is m each. Find the other pair. - True or false: “If you know a composite shape’s total area, you can always find its perimeter.” Explain.
Answers: 1.
Activities
Activity 1 — Explicit Instruction: Combining Area and Perimeter in One Problem (12 min)
Real renovation and landscaping problems usually need both — materials by area, boundary trims by perimeter.
I do — a backyard renovation. The yard is an L-shape: overall
We do — a pool deck. Overall
You do: A courtyard renovation with new dimensions and rates — find the area, perimeter, and total cost, presenting full working and a concluding sentence.
Activity 2 — Explicit Instruction: Working backwards (12 min)
Sometimes the area or perimeter is known, and a dimension must be found.
I do — backwards from area. An L-shaped room has area
We do — backwards from perimeter. An L-shaped garden (single corner notch) has perimeter
You do: Three “working backwards” problems — two from area, one from perimeter — using new dimensions.
Activity 3 — Applied Problem: the Courtyard Renovation (10 min)
Pairs. A genuine multi-step problem requiring the full toolkit.
A homeowner’s courtyard is an L-shape: the overall block is
m by m, with a rectangular garden bed removed from one corner for planting (left unpaved). Concrete paving must cover exactly — the supplier’s minimum delivery.
- Find the area of the garden bed needed to achieve this.
- If the garden bed’s width is
m, find its other side length. - Find the perimeter of the paved area, and the cost of edging at
16.50$ per metre.
Socratic scaffolding:
| Prompt | Purpose |
|---|---|
| Understand: what is fixed, and what is unknown? | The paved area ( |
| What do you know about the overall block? | |
| Devise a plan for the notch’s area | Paved area |
| Carry out | |
| Devise a plan for the missing side | Notch area |
| Carry out | |
| Now the perimeter — what shortcut applies? | Corner notch |
| Carry out | |
| Look back | Does a |
Answers: 1.
Checks for Understanding
(5 minutes — exit ticket, collected)
- A composite shape has area
, formed from a rectangle cm by cm minus a cm by cm notch. Find . - An L-shaped patio (single corner notch) has perimeter
m. One side of the bounding rectangle is m. Find the other side. - A rectangular lawn
m by m has a garden bed removed from a corner, leaving of lawn. Find the area of the garden bed. - Reasoning. Two different composite shapes both have an area of
. Must they have the same perimeter? Explain. - A paving company charges
58 \text{m}^2 $14 45\ \text{m}^2 32$ m. Find the total cost.
Answers: 1.
Common Misconceptions
| Misconception | How to pre-empt it |
|---|---|
| Multiplying perimeter by an area rate, or area by a per-metre rate. | Underline each rate’s units before multiplying, and check they match the quantity being costed. |
| Assuming equal areas imply equal perimeters (or vice versa). | Activity 2 and the CFU reasoning question confront this directly with a counterexample. |
| Working backwards with the wrong operation — dividing when multiplying was needed, or vice versa. | Write the original equation first (e.g. " |
| Forgetting to add back (or subtract) the notch when reversing a composite-area calculation. | Always re-state the original forward relationship in words before working backwards. |
| Not checking whether a deduced dimension is realistic (e.g., larger than the whole shape, or negative). | Make “looking back” a required, written step, not an afterthought. |
| Rounding a costing answer inconsistently (nearest dollar vs nearest cent). | Agree a rounding convention (usually to the cent) at the start of every costing problem. |
Enrichment — Competition-Style Problems
E1 (Kangaroo style). A square garden of side
Answer
E2 (AMC Junior style). A rectangular block of land has whole-number side lengths and area
Answer
Since the shed is a corner notch, the usable land’s perimeter equals the block’s own perimeter:
The block is
E3 (Challenge). A pentagon is a
Answer
E4 (Challenge). A rectangular garden
Answer
Using the Lesson 21 result (a middle-of-side notch increases the perimeter by twice its depth):
Homework
- A composite shape has area
, formed from a rectangle cm by cm minus a cm by cm notch. Find . - An L-shaped courtyard (single corner notch) has perimeter
m. One side of the bounding rectangle is m. Find the other side. - A rectangular oval
m by m has an equipment shed removed from a corner, leaving of usable oval. Find the area of the shed. - A paving company charges
62 \text{m}^2 $17 75\ \text{m}^2 38$ m. Find the total cost. - A square courtyard of side
has a m by m garden bed removed from a corner, leaving an area of . Find . - Reasoning. A student claims: “If two composite shapes have the same perimeter, they must have the same area.” Give a specific counterexample using two rectangles.
- Challenge. A rectangular garden
m by m has a square pond removed from the middle of one side (not a corner), with side length . The perimeter of the remaining garden edge is m. Find .
Answers: Q1 —